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KOTLIN - BUBBLE SORT CODE




Example :



class Sort {

    fun bubbleSort(arr: Array<Int>) {

        var n = arr.size;
        var temp: Int;
        for (i in 0..(n-2)) {

            // (n-i-1) is to ignore the comparisons that is already done.

            for(j in 0..(n-i-2)) {

                if(arr[j] > arr[j+1] ) {

                    temp = arr[j];
                    arr[j] = arr[j+1];
                    arr[j+1] = temp;
                }
            }
        }
    }
}

fun main(args: Array<String>) {
    var arr = arrayOf(7, 4, 8, 1, 6);

    var sort = Sort();
    sort.bubbleSort(arr);

    for(i in 0..(arr.size-1)) {

        print("${arr[i]}, ");
    }
}


Output :



  1, 4, 6, 7, 8,

We are just concerned about the fun bubbleSort(arr: Array<Int>) method, where the sorting logic is defined.


We have the array


var arr = arrayOf(7, 4, 8, 1, 6);

Which we have passed to the bubbleSort(..) method.


In the bubbleSort(..) method, we have taken the count of the elements of the array.


var n = arr.size;

Now, let us corelate this code with the explanation of Bubble Sort.


Let us take the same diagram.

java_Collections

And take the chunk of code and explain it.


for(j in 0..(n-i-2)) {

	if(arr[j] > arr[j+1] ) {

		temp = arr[j];
		arr[j] = arr[j+1];
		arr[j+1] = temp;
	}
}

So, the outer loop, i.e.


for(j in 0..(n-i-2))

Determines the Passes. If you see the above explanation you can find the first pass,


1st Pass (i.e. When i=0)


Then comes the the inner loop, i.e.


for(j in 0..(n-i-2))

Which determines the iterations.

java_Collections

Next, comes the comparison where we compare 1st and 2nd element. And if the 1st element is greater than 2nd element we swap it.


if(arr[j] > arr[j+1] ) {

	temp = arr[j];
	arr[j] = arr[j+1];
	arr[j+1] = temp;
}

Where arr[j] refers to the first element i.e. 7 and arr[j+1] refers to the second element i.e. 4.


And continue in the same pattern.


Note : (n-i-2) in the conditional part of inner loop ignores the last element from each passes.

Efficiency / Running time of Bubble Sort


If we consider the Bubble Sort Algorithm, there are two loops. Firstly, there is the for loop. And inside the for loop there is also a for loop.


The for loop executes n times(Assuming the array contains n elements).


Now, for each iteration of for loop, the nested for loop also executes approximately n times.


Which means for 1st iteration of for loop,


the nested for loop also runs n time.

Similarly, for 2nd iteration of for loop,


inner for loop runs (n-1) times.

Similarly, for nth iteration of for loop,


inner for loop runs 1 time.

So, the running time is close to n*n or n^2.


So, in worst case the running time is O(n^2).


Note : Worst case is the scenario where the array elements are all sorted in descending order. i.e. 8, 7, 6, 4, 1.