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PYTHON - LINEAR SEARCH CODE




Example :



def search(arr, n):     
	for i in range(len(arr)):
		if(arr[i] == n):
			return i
	return -1

arr = [5, 3, 6, 2, 1, 4]
n = 2 # Element to be searched.

print("The Array elements are : ")

for i in range(len(arr)):
	print(arr[i])

print("\nElement to be searched :", n)

index = search(arr, n)

if(index == -1):
	print("Element is not present in the array")
else:
	print("The element", n, "is present at index", index)


Output :



  The Array elements are :
  5
  3
  6
  2
  1
  4

  Element to be searched : 2
  The element 2 is present at index 3

Code explanation


The above code is quite simple,


We will be searching the element 2,


n = 2  # Element to be searched.

From the array,


arr = [5, 3, 6, 2, 1, 4]

Next, we pass the array and the element 2, to the search(...) method.


index = search(arr, n)

Explanation of the 'def search(arr, n)' method :


def search(arr, n):
	for i in range(len(arr)):
		if(arr[i] == n):
			return i
	return -1

We need to search the element 2 from the below array.

java_Collections

So, we run a for loop. Starting from the 1st location to the end of the array.


for i in range(len(arr)):
	if(arr[i] == n):
		return i

And at every step, we keep on checking if the element is present in the array or not.


if(arr[i] == n):
	return i

If we find the element, we return that particular location.


return i
java_Collections


But, what if we are searching for an element that is not present in the array?


Say, we are searching for number 8. Which is not present in the array.


In that case, we return -1.


return -1

Which states the number is not found.


Finally, the returned value is stored in the index variable.


index = search(arr, n)

And we print it using :


print("The element", n, "is present at index", index)

Output :



  The Array elements are :
  5
  3
  6
  2
  1
  4

  Element to be searched : 2
  The element 2 is present at index 3